Actor Gary Lockwood has the distinction of being “killed” by two of the more iconic characters in SciFi — Captain James T. Kirk and HAL9000.
(Now if only we had the chance to see Kirk and HAL9000 face off directly…)
Actor Gary Lockwood has the distinction of being “killed” by two of the more iconic characters in SciFi — Captain James T. Kirk and HAL9000.
(Now if only we had the chance to see Kirk and HAL9000 face off directly…)
A frighteningly time-wasting site where you can look up the TV shows and toys you frittered away your childhood on. You know you can’t resist…
Well, here’s a local example.
According to this article from E&P, the Globe‘s daily subscriber count has dropped to under 400,000 in an 8.5% decline from the same six-month period a year ago.
This might be a first — the appearance of (which is clearly supposed to be) Thevenin and Norton equivalents in a mainstream comic strip.
Take a look.
He’s even right. A circuit of sources and resistors with only two external terminals can be collapsed down down to two forms, all three of which will yield identical results when you take measurements from those terminals.
The key measurements are the open-circuit voltage (Voc) across the terminals and the short-circuit current (Isc) through the terminals. From those you calculate the Thevenin resistance RT = Voc/Isc.
The Thevenin form is an ideal voltage source of Voc in series with RT with the external terminals being connected to the “free” end of RT and the “free” end of the voltage source. The Norton form is an ideal current source of Isc in parallel with RT and the external terminals being connected across RT.
So indeed, even when nothing is connected to the terminals, the Norton form will be pumping current through the resistor while the Thevenin form will be quiescent. So Alex is quite right that the Norton form will be warmer.